Product $(A)$ of the reaction is:

An ester $(A)$ with molecular formula $C_9H_{10}O_2$ is reacted with an excess of $CH_3MgBr$. The resulting product is treated with concentrated $H_2SO_4$ to form an olefin $(B)$. Ozonolysis of $(B)$ yields a ketone with the formula $C_8H_8O$. What is the structure of $(A)$?

In the given reaction: $NH_2-CH_2-CH_2-NH_2 + C_2H_5OOC-COOC_2H_5 \xrightarrow{\text{Pyridine}} [X]$,$[X]$ will be:

Match the reactant in Column-$I$ with the reaction in Column-$II$:

Column-$I$	Column-$II$
$(i)$ Acetic acid	$(a)$ Stephen
$(ii)$ Sodium phenate	$(b)$ Friedel-Crafts
$(iii)$ Methyl cyanide	$(c)$ $HVZ$
$(iv)$ Toluene	$(d)$ Kolbe's

$\text{CH}_3\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{X} \xrightarrow{\text{PCl}_5} \text{Y} \xrightarrow{\text{Alcoholic KOH}} \text{Z}$. Find product '$Z$' in the above reaction.

The product $(X)$ of the reaction is: