How is the t_{2g}^4 e_g^0 configuration possi | vedclass

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(D) In an octahedral complex,the $d$-orbitals split into two sets: $t_{2g}$ (lower energy) and $e_g$ (higher energy).For a $d^4$ ion,if the crystal fi

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$\Delta_0 > P$

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(D) In an octahedral complex,the $d$-orbitals split into two sets: $t_{2g}$ (lower energy) and $e_g$ (higher energy).For a $d^4$ ion,if the crystal field splitting energy $(\Delta_0)$ is greater than the pairing energy $(P)$,the electrons will prefer to pair up in the lower energy $t_{2g}$ orbitals rather than occupying the higher energy $e_g$ orbitals.This results in a low-spin configuration of $t_{2g}^4 e_g^0$.Therefore,the condition for this configuration is $\Delta_0 > P$.

How is the $t_{2g}^4 e_g^0$ configuration possible for a $d^4$ ion during crystal field splitting in an octahedral complex?

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