$[Fe(CN)_6]^{4-}$ and $[Fe(H_2O)_6]^{2+}$ show different colours in dilute solution because

  • A
    $CN^{-}$ is a strong field ligand and $H_2O$ is a weak field ligand,hence the magnitude of $CFSE$ is different
  • B
    both $CN^{-}$ and $H_2O$ absorb the same wavelength of energy
  • C
    complexes of weak field ligands are generally colourless
  • D
    the sizes of $CN^{-}$ and $H_2O$ are different,hence their colours are also different

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Similar Questions

Match List-$I$ with List-$II$.
List-$I$ (Chromium $(III)$ Complexes) - List-$II$ ($\Delta_o$ $(cm^{-1})$)
$A$. $[Cr(CN)_6]^{3-}$ - $I$. $15,060$
$B$. $[CrF_6]^{3-}$ - $II$. $17,400$
$C$. $[Cr(H_2O)_6]^{3+}$ - $III$. $22,300$
$D$. $[Cr(en)_3]^{3+}$ - $IV$. $26,600$
Choose the correct answer from the options given below:

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

The increasing order of field strength of ligands is:

The complex with the highest magnitude of crystal field splitting energy $\left(\Delta_0\right)$ is

Which complex shows the highest crystal field stabilisation energy?

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