Highest $(+7) $ oxidation state is shown by
Highest $(+7) $ oxidation state is shown by
- [AIIMS 1999]
- [AIPMT 1994]
- [AIPMT 2002]
- A
$Co$
- B
$Cr$
- C
$V$
- D
$Mn$
Similar Questions
The 'spin only' magnetic moment value of $\mathrm{MO}_4{ }^{2-}$ is . . . . . BM. (Where $\mathrm{M}$ is a metal having least metallic radii. among $\mathrm{Sc}, \mathrm{Ti}, \mathrm{V}, \mathrm{Cr}, \mathrm{Mn}$ and $\mathrm{Zn}$ ).
(Given atomic number: $\mathrm{Sc}=21, \mathrm{Ti}=22, \mathrm{~V}=23$, $\mathrm{Cr}=24, \mathrm{Mn}=25$ and $\mathrm{Zn}=30)$
The 'spin only' magnetic moment value of $\mathrm{MO}_4{ }^{2-}$ is . . . . . BM. (Where $\mathrm{M}$ is a metal having least metallic radii. among $\mathrm{Sc}, \mathrm{Ti}, \mathrm{V}, \mathrm{Cr}, \mathrm{Mn}$ and $\mathrm{Zn}$ ).
(Given atomic number: $\mathrm{Sc}=21, \mathrm{Ti}=22, \mathrm{~V}=23$, $\mathrm{Cr}=24, \mathrm{Mn}=25$ and $\mathrm{Zn}=30)$
- [JEE MAIN 2024]
Ionisation enthalpies of $Ce,\,Pr$ and $Nd$ are higher than $Th,\,Pa$ and $U$. Why ?
Ionisation enthalpies of $Ce,\,Pr$ and $Nd$ are higher than $Th,\,Pa$ and $U$. Why ?
By annealing, steel
By annealing, steel
Properties common to the elements manganese, iron, cobalt, nickel and copper include the ready formation by them all of
$(I)$ coloured ions in aqueous solution
$(II)$ oxides of nitrogen are formed on reaction with concentrated $HNO_3$
$(III)$ chlorides of formula $MCl_2$ and $MCl_3$
Properties common to the elements manganese, iron, cobalt, nickel and copper include the ready formation by them all of
$(I)$ coloured ions in aqueous solution
$(II)$ oxides of nitrogen are formed on reaction with concentrated $HNO_3$
$(III)$ chlorides of formula $MCl_2$ and $MCl_3$
Effective magnetic moment of $S{c^{ + 3}}$ ion is
Effective magnetic moment of $S{c^{ + 3}}$ ion is