The 'spin only' magnetic moment value of MO_4 | vedclass

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(A) The metallic radii of the given elements generally decrease across the period due to increasing effective nuclear charge,but $Zn$ has a larger rad

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(A) The metallic radii of the given elements generally decrease across the period due to increasing effective nuclear charge,but $Zn$ has a larger radius due to metallic bonding characteristics. Among the transition metals $Sc$ to $Mn$,the atomic radius decreases. However,the question asks for the least metallic radii among the listed elements. $Cr$ has a smaller radius than $Sc, Ti, V$ and $Mn$.In $CrO_4^{2-}$,the oxidation state of $Cr$ is $x + 4(-2) = -2$,so $x = +6$.The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.The electronic configuration of $Cr^{6+}$ is $[Ar] 3d^0$.Since there are no unpaired electrons $(n=0)$,the spin-only magnetic moment $\mu = \sqrt{n(n+2)} = \sqrt{0(0+2)} = 0 \ BM$.

The 'spin only' magnetic moment value of $MO_4^{2-}$ is . . . . . $BM$. (Where $M$ is a metal having least metallic radii among $Sc, Ti, V, Cr, Mn$ and $Zn$).
(Given atomic number: $Sc=21, Ti=22, V=23, Cr=24, Mn=25$ and $Zn=30$)

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The 'spin only' magnetic moment value of $MO_4^{2-}$ is . . . . . $BM$. (Where $M$ is a metal having least metallic radii among $Sc, Ti, V, Cr, Mn$ and $Zn$).(Given atomic number: $Sc=21, Ti=22, V=23, Cr=24, Mn=25$ and $Zn=30$)