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Question

(B) For a process at constant pressure,the heat supplied is given by $\Delta Q = n C_p \Delta T$. The change in internal energy is given by $\Delta U

Vedclass · Accepted Answer

$7: 5: 2$

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(B) For a process at constant pressure,the heat supplied is given by $\Delta Q = n C_p \Delta T$. The change in internal energy is given by $\Delta U = n C_v \Delta T$. The work done is given by $\Delta W = P \Delta V = n R \Delta T$. Thus,the ratio $\Delta Q : \Delta U : \Delta W = C_p : C_v : R$. For a rigid diatomic gas,the degrees of freedom $f = 5$. Therefore,$C_v = \frac{f}{2} R = \frac{5}{2} R$ and $C_p = C_v + R = \frac{7}{2} R$. Substituting these values,we get $\Delta Q : \Delta U : \Delta W = \frac{7}{2} R : \frac{5}{2} R : R$. Multiplying by $\frac{2}{R}$,we obtain the ratio $7 : 5 : 2$.

Heat is applied to a rigid diatomic gas at constant pressure. The ratio $\Delta Q : \Delta U : \Delta W$ is

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