Had Ajita scored 10 more marks in her mathema | vedclass

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Question

(A) Let her actual marks be $x$.According to the problem,if she scored $10$ more marks,the new score would be $(x + 10)$.The condition states that $9$

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) Let her actual marks be $x$.According to the problem,if she scored $10$ more marks,the new score would be $(x + 10)$.The condition states that $9$ times these marks would be the square of her actual marks:$9(x + 10) = x^2$$9x + 90 = x^2$Rearranging the terms to form a quadratic equation:$x^2 - 9x - 90 = 0$Factoring the quadratic equation:$x^2 - 15x + 6x - 90 = 0$$x(x - 15) + 6(x - 15) = 0$$(x + 6)(x - 15) = 0$This gives $x = -6$ or $x = 15$.Since marks cannot be negative,we discard $x = -6$.Therefore,the actual marks obtained by Ajita is $15$.

Had Ajita scored $10$ more marks in her mathematics test out of $30$ marks,$9$ times these marks would have been the square of her actual marks. How many marks did she get in the test?

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