(N/A) The total energy of a system is given by $E = P.E. + K.E.$,which implies $K.E. = E - P.E.$. Since kinetic energy $(K.E.)$ must be non-negative,the particle cannot exist in regions where $P.E. > E$.
$(i)$ For the first figure: The particle cannot exist in the region $x > a$ because $V(x) = V_0 > E$. The minimum total energy required is $0$.
(ii) For the second figure: The potential energy $V(x)$ is greater than $E$ in all regions shown. Thus,the particle cannot exist in any of these regions. The minimum total energy required is $V_0$.
(iii) For the third figure: The particle cannot exist in regions where $V(x) > E$. Here,$V(x) = V_0$ for $x < a$ and $x > b$. Thus,the particle is confined to $a < x < b$. The minimum total energy required is $-V_1$.
(iv) For the fourth figure: The particle cannot exist where $V(x) > E$. Based on the graph,this occurs for $x < -b/2$,$-a/2 < x < a/2$,and $x > b/2$. The particle can only exist in the regions $-b/2 < x < -a/2$ and $a/2 < x < b/2$. The minimum total energy required is $-V_1$.