The reaction of 3-phenylpropene with HBr give | vedclass

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Question

(B) The reaction of $3$-phenylpropene $(C_6H_5CH_2CH=CH_2)$ with $HBr$ follows Markovnikov's rule.In the first step,the electrophile $H^+$ attacks the

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$C_6H_5CH_2CH(Br)CH_3$

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(B) The reaction of $3$-phenylpropene $(C_6H_5CH_2CH=CH_2)$ with $HBr$ follows Markovnikov's rule.In the first step,the electrophile $H^+$ attacks the terminal carbon $(C_3)$ to form a more stable carbocation.The intermediate formed is a secondary benzylic carbocation $(C_6H_5CH_2CH^+CH_3)$,which is stabilized by resonance with the phenyl ring.Subsequently,the nucleophile $Br^-$ attacks the carbocation to form the major product,$1$-phenyl-$2$-bromopropane $(C_6H_5CH_2CH(Br)CH_3)$.

The reaction of $3$-phenylpropene with $HBr$ gives (as the major product):

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