$A$ particle is executing $S.H.M.$ Then the graph of acceleration as a function of displacement is

$A$ particle of mass $10 \,g$ is undergoing $S.H.M.$ with an amplitude of $10 \,cm$ and a period of $0.1 \,s$. The maximum value of the force on the particle is about ............ $N$.

$A$ body oscillates with $S.H.M.$ according to the equation $x = (5.0 \, m) \cos [(2 \pi \, rad \, s^{-1}) t + \pi / 4]$. At $t = 1.5 \, s$,its acceleration is ....... $m / s^2$.

The $x-t$ graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at $t=2 \ s$ is:

$A$ particle is in linear simple harmonic motion between two points,$A$ and $B$,$10 \; cm$ apart. Take the direction from $A$ to $B$ as the positive direction and give the signs of velocity,acceleration,and force on the particle when it is:
$(a)$ at the end $A$.
$(b)$ at the end $B$.
$(c)$ at the mid-point of $AB$ going towards $A$.
$(d)$ at $2 \; cm$ away from $B$ going towards $A$.
$(e)$ at $3 \; cm$ away from $A$ going towards $B$.
$(f)$ at $4 \; cm$ away from $B$ going towards $A$.

Obtain the force law for $SHM$ from the displacement of $SHM$ particle.