(D) The mass of the particle is $m = 10 \, g = 10 \times 10^{-3} \, kg = 0.01 \, kg$.The amplitude is $A = 0.5 \, m$.The angular frequency is $\omega

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) The mass of the particle is $m = 10 \, g = 10 \times 10^{-3} \, kg = 0.01 \, kg$.The amplitude is $A = 0.5 \, m$.The angular frequency is $\omega = 10 \, rad/s$.The maximum force $F_{max}$ in simple harmonic motion is given by the formula $F_{max} = m \omega^2 A$.Substituting the values: $F_{max} = 0.01 \times (10)^2 \times 0.5$.$F_{max} = 0.01 \times 100 \times 0.5$.$F_{max} = 1 \times 0.5 = 0.5 \, N$.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

Easy

$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?

A
$25$
B
$5$
C
$2.5$
D
$0.5$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Oscillations

Subtopic

Acceleration and Force of Simple Harmonic Motion

In a simple harmonic motion,let $f$ be the acceleration and $T$ be the time period. If $x$ denotes the displacement,then the $|fT|$ vs. $x$ graph will look like,

EasyWBJEE 2023

View Solution

The $x-t$ graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at $t = 4/3 \,s$ is

MediumIIT 2009

View Solution

$A$ particle of mass $5 \,g$ is executing $S.H.M.$ with an amplitude $0.3 \,m$ and period $\frac{\pi}{5} \,s$. The maximum value of the force acting on the particle is (in $\,N$)

EasyMHT CET 2021

View Solution

The displacement of a particle varies with time as $x = 12 \sin \omega t - 16 \sin^3 \omega t$ (in $cm$). If its motion is $S.H.M.$,then its maximum acceleration is

Medium

View Solution

$Assertion :$ In $SHM$,acceleration is always directed towards the mean position.
$Reason :$ In $SHM$,the body has to stop momentarily at the extreme position and move back to the mean position.

EasyAIIMS 2009

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?

Similar Questions

In a simple harmonic motion,let $f$ be the acceleration and $T$ be the time period. If $x$ denotes the displacement,then the $|fT|$ vs. $x$ graph will look like,

The $x-t$ graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at $t = 4/3 \,s$ is

$A$ particle of mass $5 \,g$ is executing $S.H.M.$ with an amplitude $0.3 \,m$ and period $\frac{\pi}{5} \,s$. The maximum value of the force acting on the particle is (in $\,N$)

The displacement of a particle varies with time as $x = 12 \sin \omega t - 16 \sin^3 \omega t$ (in $cm$). If its motion is $S.H.M.$,then its maximum acceleration is

$Assertion :$ In $SHM$,acceleration is always directed towards the mean position.$Reason :$ In $SHM$,the body has to stop momentarily at the extreme position and move back to the mean position.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Assertion :$ In $SHM$,acceleration is always directed towards the mean position.
$Reason :$ In $SHM$,the body has to stop momentarily at the extreme position and move back to the mean position.