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(B) To determine if $(x-1)$ is a factor of the polynomial $p(x) = x^{3}+6x^{2}-9x-14$,we use the Factor Theorem.According to the Factor Theorem,$(x-c)

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(B) To determine if $(x-1)$ is a factor of the polynomial $p(x) = x^{3}+6x^{2}-9x-14$,we use the Factor Theorem.According to the Factor Theorem,$(x-c)$ is a factor of $p(x)$ if $p(c) = 0$.Here,$c = 1$.Substitute $x = 1$ into the polynomial:$p(1) = (1)^{3} + 6(1)^{2} - 9(1) - 14$$p(1) = 1 + 6 - 9 - 14$$p(1) = 7 - 23$$p(1) = -16$Since $p(1) 
eq 0$,$(x-1)$ is not a factor of the given polynomial.

From the following polynomials,find out which of them has $(x-1)$ as a factor:
$x^{3}+6x^{2}-9x-14$

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From the following polynomials,find out which of them has $(x-1)$ as a factor:$x^{3}+6x^{2}-9x-14$