For uniform circular motion write equation of centripetal force, centripetal acceleration. Also write examples.
When body of mass $\mathrm{m}$ moves on circular path of radius $\mathrm{R}$ with constant speed $v$, it has centripetal or radial acceleration $a=\frac{v^{2}}{\mathrm{R}}$. Direction of acceleration is toward centre of the circle which is shown in figure.
By Newton's second law of motion necessary force to provide this acceleration $f_{c}=\frac{m v^{2}}{\mathrm{R}}$. Direction of this force is toward centre of the circle hence this force is called centripetal force.
In different situation centripetal force is provided as follows :
$(1) $For planet revolving around the Sun necessary centripetal is provided by gravitational force.
$(2)$ For electron revolving around the nucleus in atom necessary centripetal force is provided by Coulombian force (electric force).
$(3)$ For vehicles moving on level circular track necessary centripetal force is provided by friction force, between tyre and road.
A car of mass $1000\,kg$ negotiates a banked curve of radius $90\,m$ on a frictionless road. If banking angle is $45^o$ , the maximum speed of car is ............ $m/s$ $[g = 10\,m/s^2]$
A block of $200\, g$ mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius $20\, cm$. If the block takes $40\, s$ to complete one round, the normal force by the side walls of the groove is
If the radius of curvature of the path of two particles of same mass are in the ratio $3:4,$ then in order to have constant centripetal force, their velocities will be in the ratio of:
Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v_0$, then the ratio of tensions in the three sections of the string is
A car turns a corner on a slippery road at a constant speed of $10\,m/s$. If the coefficient of friction is $0.5$, the minimum radius of the arc in meter in which the car turns is