(D) The normal force $N$ provides the necessary centripetal force for circular motion.$N = F_c = m \omega^2 R$Since $\omega = \frac{2\pi}{T}$,we have

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) The normal force $N$ provides the necessary centripetal force for circular motion.$N = F_c = m \omega^2 R$Since $\omega = \frac{2\pi}{T}$,we have $N = m \left( \frac{2\pi}{T} \right)^2 R = m \frac{4\pi^2}{T^2} R$.Given values: $m = 200\, g = 0.2\, kg$,$R = 20\, cm = 0.2\, m$,and $T = 40\, s$.Substituting these values into the formula:$N = 0.2 \times \frac{4 \times (3.14159)^2}{(40)^2} \times 0.2$$N = 0.2 \times \frac{4 \times 9.8696}{1600} \times 0.2$$N = 0.04 \times \frac{39.4784}{1600}$$N = 0.04 \times 0.024674 = 9.8696 \times 10^{-4}\, N$.Rounding to the nearest option,we get $N \approx 9.859 \times 10^{-4}\, N$.

Class 11 Physics 3-2.Motion in Plane Dynamics of circular Motion (Centrifugal force) and Pendulum and Motion on Curved path

Difficult

$A$ block of $200\, g$ mass moves with a uniform speed in a horizontal circular groove,with vertical side walls of radius $20\, cm$. If the block takes $40\, s$ to complete one round,the normal force by the side walls of the groove is

JEE MAIN 2021 All JEE MAIN

A
$0.0314\, N$
B
$9.859 \times 10^{-2}\, N$
C
$6.28 \times 10^{-3}\, N$
D
$9.859 \times 10^{-4}\, N$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

3-2.Motion in Plane

Subtopic

Dynamics of circular Motion (Centrifugal force) and Pendulum and Motion on Curved path

Previous Year

JEE MAIN 2021 Paper All JEE MAIN years →

$A$ particle of mass $m$ is rotating in a circular path of radius $r$. Its angular momentum is $L$. The centripetal force acting on it is $F$. The relation between $F$,$L$,$r$,and $m$ is

MediumMHT CET 2024

View Solution

$A$ dumbbell is placed on a frictionless horizontal table. Sphere $A$ is attached to a frictionless pivot so that $B$ can be made to rotate about $A$ with constant angular velocity. If $B$ (mass $2M$) makes one revolution in period $P$,the tension in the rod (length $d$) is

Difficult

View Solution

$A$ string of length '$L$' fixed at one end carries a mass '$m$' at the other end. The string makes $\frac{3}{\pi}$ r.p.s. around the vertical axis through the fixed end. The tension in the string is (in $mL$)

MediumMHT CET 2022

View Solution

$A$ boy on a cycle pedals around a circle of $20\, m$ radius at a speed of $20\, m/s$. The combined mass of the boy and the cycle is $90\, kg$. The angle that the cycle makes with the vertical so that it may not fall is ......... $^o$ $(g = 9.8\, m/s^2)$.

Easy

View Solution

$A$ string of length ' $\ell$ ' fixed at one end carries a mass 'm' at the other end. The string makes $\frac{3}{\pi}$ revolutions per second around the vertical axis through the fixed end as shown in the figure. The tension '$T$' in the string is:

DifficultMHT CET 2020

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ block of $200\, g$ mass moves with a uniform speed in a horizontal circular groove,with vertical side walls of radius $20\, cm$. If the block takes $40\, s$ to complete one round,the normal force by the side walls of the groove is

Similar Questions

$A$ particle of mass $m$ is rotating in a circular path of radius $r$. Its angular momentum is $L$. The centripetal force acting on it is $F$. The relation between $F$,$L$,$r$,and $m$ is

$A$ dumbbell is placed on a frictionless horizontal table. Sphere $A$ is attached to a frictionless pivot so that $B$ can be made to rotate about $A$ with constant angular velocity. If $B$ (mass $2M$) makes one revolution in period $P$,the tension in the rod (length $d$) is

$A$ string of length '$L$' fixed at one end carries a mass '$m$' at the other end. The string makes $\frac{3}{\pi}$ r.p.s. around the vertical axis through the fixed end. The tension in the string is (in $mL$)

$A$ boy on a cycle pedals around a circle of $20\, m$ radius at a speed of $20\, m/s$. The combined mass of the boy and the cycle is $90\, kg$. The angle that the cycle makes with the vertical so that it may not fall is ......... $^o$ $(g = 9.8\, m/s^2)$.

$A$ string of length ' $\ell$ ' fixed at one end carries a mass 'm' at the other end. The string makes $\frac{3}{\pi}$ revolutions per second around the vertical axis through the fixed end as shown in the figure. The tension '$T$' in the string is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module