For the reaction $A + B \to C$,it is found that doubling the concentration of $A$ increases the rate by $4$ times,and doubling the concentration of $B$ doubles the reaction rate. What is the overall order of the reaction?

  • A
    $4$
  • B
    $3/2$
  • C
    $3$
  • D
    $1$

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Similar Questions

For the reaction $A + B \rightarrow C$,we have the following data:
Initial concentration of $A$ $(M)$Initial concentration of $B$ $(M)$Initial Rate $(M \cdot s^{-1})$
$1$$10$$100$
$1$$1$$1$
$10$$1$$10$

The order of the reaction with respect to $A$ and $B$ are:

The reaction between $X$ and $Y$ is first order with respect to $X$ and zero order with respect to $Y$.
$Experiment$ $[X] / (mol \ L^{-1})$ $[Y] / (mol \ L^{-1})$ $\text{Initial rate} / (mol \ L^{-1} \ min^{-1})$
$I$ $0.1$ $0.1$ $2 \times 10^{-3}$
$II$ $0.2$ $0.2$ $4 \times 10^{-3}$
$III$ $0.4$ $0.4$ $M \times 10^{-3}$
$IV$ $0.1$ $0.2$ $2 \times 10^{-3}$

Examine the data of the table and calculate the ratio of the numerical value of $M$ to $0.2$.

The rate of reaction,$A + B + C \longrightarrow P$ is given by
$r = K[A]^{1/2} [B]^{1/2} [C]^{1/4}$
The order of reaction is

For the reaction $A + B \to$ products,doubling the concentration of $A$ the rate of the reaction is doubled,but on doubling the concentration of $B$ the rate remains unaltered. The overall order of the reaction is:

The unit of the rate constant depends on which of the following?

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