For the reaction $2HI$ $\rightleftharpoons$ ${H_2} + {I_2}$, the rate of the reaction is proportional to ${[HI]^2}$. This means that the reaction is
Unimolecular
Bimolecular
Of first order
Of second order
The experimental data for the reaction $2A + {B_2} \to 2AB$ isThe rate equation for the above data is
Exp. |
$[A]_0$ |
$[B]_0$ |
Rate (mole $s^{-1}$) |
$(1)$ |
$0.50$ |
$0.50$ |
$1.6 \times {10^{ - 4}}$ |
$(2)$ |
$0.50$ |
$1.00$ |
$3.2 \times {10^{ - 4}}$ |
$(3)$ |
$1.00$ |
$1.00$ |
$3.2 \times {10^4}$ |
Order of a reaction is decided by
The inversion of cane sugar is represented by${C_{12}}{H_{22}}{O_{11}} + {H_2}O \to {C_6}{H_{12}}{O_6} + {C_6}{H_{12}}{O_6}$ It is a reaction of
Consider the following reaction,
$2 H _2( g )+2 NO ( g ) \rightarrow N _2( g )+2 H _2 O ( g )$
which following the mechanism given below:
$2 NO ( g ) \underset{ k _{-1}}{\stackrel{ k _1}{\rightleftharpoons}} N _2 O _2( g )$
$N _2 O _2( g )+ H _2( g ) \stackrel{ k _2}{\rightleftharpoons} N _2 O ( g )+ H _2 O ( g )$
$N _2 O ( g )+ H _2( g ) \stackrel{ k _3}{\rightleftharpoons} N _2( g )+ H _2 O ( g )$
(fast equilibrium)
(slow reaction)
(fast reaction)
The order of the reaction is
In a reaction $A_2B_3(g) \to A_2(g) + \frac{3}{2}B_2(g)$, the pressure increases from $60$ torr to $75$ torr in $2.5\, minutes$. The rate of disappearance of $A_2B_3$ is ........ $torr\, min^{-1}$