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(A) In circuit $(A)$,the impedance is $Z_A = R = 40 \ \Omega$.In circuit $(B)$,the impedance is $Z_B = \sqrt{R^2 + (X_L - X_C)^2}$.Since $Z_B = \sqrt{

Vedclass · Accepted Answer

The r.m.s. current in circuit $(B)$ can never be greater than that in circuit $(A)$.

Vedclass · Answer

(A) In circuit $(A)$,the impedance is $Z_A = R = 40 \ \Omega$.In circuit $(B)$,the impedance is $Z_B = \sqrt{R^2 + (X_L - X_C)^2}$.Since $Z_B = \sqrt{R^2 + (X_L - X_C)^2} \ge R$,it follows that $Z_B \ge Z_A$.The r.m.s. current is given by $I = V/Z$. Since the voltage $V$ is the same $(220 \ V)$ for both circuits,$I_B = V/Z_B$ and $I_A = V/Z_A$.Since $Z_B \ge Z_A$,it implies $I_B \le I_A$. Thus,the r.m.s. current in circuit $(B)$ can never be greater than that in circuit $(A)$.

For the given figure,choose the correct option.

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