Draw phasor diagrams for $X_C > X_L$ and $X_C < X_L$,and state the disadvantages of the phasor method.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) If $X_C > X_L$,the phase angle $\phi$ is positive and the circuit becomes capacitive; consequently,the current in the circuit leads the source voltage.
If $X_C < X_L$,the phase angle $\phi$ is negative and the circuit becomes inductive; consequently,the source voltage in the circuit leads the current.
The phasor diagram and the variation of $V$ and $I$ with $\omega t$ for the case $X_C > X_L$ are shown in the figure.
Thus,we have obtained the amplitude and phase of the current for an $LCR$ series circuit using the technique of phasors,but this method has certain disadvantages:
$1$. The phasor diagram provides no information about the initial conditions.
$2$. One can choose any arbitrary value of $t$ and draw different phasors. The solution obtained is called the steady-state solution,which is not a general solution.
$3$. Furthermore,there exists a transient solution that persists even for $V = 0$.
The general solution is the sum of the transient solution and the steady-state solution. After a sufficiently long time,the effects of the transient solution die out,and the behavior of the circuit is described by the steady-state solution.

Explore More

Similar Questions

For the given figures,choose the correct option:

Obtain the relation of phase between instantaneous current and voltage with the help of a phasor diagram for a series $LCR$ circuit.

In a circuit,$L$,$C$,and $R$ are connected in series with an alternating voltage source of frequency $f$. When the current in the circuit leads the voltage by $45^{\circ}$,the value of $C$ is

As shown in the figure,a series circuit connected across a $200 \,V, 60 \,Hz$ line consists of a capacitor of capacitive reactance $X_C = 30 \,\Omega$,a non-inductive resistor of $R_1 = 44 \,\Omega$,and a coil of inductive reactance $X_L = 90 \,\Omega$ and resistance $R_2 = 36 \,\Omega$. The power dissipated in the coil is.....$W$

$A$ series $LCR$ circuit consists of an inductor $L$,a capacitor $C$,and a resistor $R$ connected across a source of emf $\varepsilon = \varepsilon_0 \sin \omega t$. When $\omega L = \frac{1}{\omega C}$,the current in the circuit is $I_0$. If the angular frequency of the source is changed to $\omega^{\prime}$,the current in the circuit becomes $\frac{I_0}{2}$. Then,the value of $\left|\omega^{\prime} L - \frac{1}{\omega^{\prime} C}\right|$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo