For the given diagram when block $B$ is pulled with velocity $V$ then velocity of block $A$ will be :-
$V$
$\frac{V}{\sqrt 3}$
$V \sqrt 3$
$\frac{\sqrt 3}{2}V$
A truck of mass $M$ is at rest on frictionless road when a monkey of mass $m$ starts moving on the truck in forward direction.If the truck recoils with a speed $v$ backward on the road, with what velocity is the monkey moving with respect to truck ?
Two blocks of same mass $(4\ kg)$ are placed according to diagram. Initial velocities of bodies are $4\ m/s$ and $2\ m/s$ and the string is taut. Find the impulse on $4\ kg$ when the string again becomes taut .......... $N-s$
In the figure shown the block $B$ moves down with a velocity $10 m/s$. The velocity of $A$ in the position shown is ......... $m/s$
A slider block $A$ moves downward at a speed of $v_A = 2\ m/s$ , at an angle of $75^o$ with horizontal as shown in the figure. The velocity with respect to $A$ of the portion of belt $B$ between ideal pulleys $C$ and $D$ is $v_{CD/A} = 2\ m/s$ at an angle $\theta $ with the horizontal. The magnitude of velocity of portion $CD$ of the belt when $\theta = 15^o$ is .......... $m/s$