અઋણ પૂર્ણાંકો $n$ માટે,$f(n) = \frac{\sum_{k=0}^n \sin \left(\frac{k+1}{n+2} \pi\right) \sin \left(\frac{k+2}{n+2} \pi\right)}{\sum_{k=0}^n \sin ^2\left(\frac{k+1}{n+2} \pi\right)}$ લો. ધારો કે $\cos ^{-1} x$ એ $[0, \pi]$ માં કિંમતો લે છે,તો નીચેનામાંથી કયા વિકલ્પો સાચા છે?
$(1)$ $\sin \left(7 \cos ^{-1} f(5)\right)=0$
$(2)$ $f(4)=\frac{\sqrt{3}}{2}$
$(3)$ $\lim _{n \rightarrow \infty} f(n)=\frac{1}{2}$
$(4)$ જો $\alpha=\tan \left(\cos ^{-1} f(6)\right)$ હોય,તો $\alpha^2+2 \alpha-1=0$

  • A
    $1, 2, 3$
  • B
    $1, 2, 4$
  • C
    $1, 2$
  • D
    $2, 3$

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$\cos 2(\theta + \phi) - 4\cos (\theta + \phi)\sin \theta \sin \phi + 2\sin^2 \phi = $

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જો $\sin \theta + \sin^2 \theta = 1$ અને $\cos^{12} \theta + a \cos^{10} \theta + b \cos^8 \theta + c \cos^6 \theta + d = 0$ હોય,તો:

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