For each question,select the proper option fr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $x = 4.185185185...$ (Equation $1$)Since there are $3$ repeating digits,multiply by $1000$:$1000x = 4185.185185...$ (Equation $2$)Subtract Equ

Vedclass · Accepted Answer

$4 \frac{5}{27}$

Vedclass · Answer

(B) Let $x = 4.185185185...$ (Equation $1$)Since there are $3$ repeating digits,multiply by $1000$:$1000x = 4185.185185...$ (Equation $2$)Subtract Equation $1$ from Equation $2$:$1000x - x = 4185.185185... - 4.185185...$$999x = 4181$$x = \frac{4181}{999}$Now,convert to a mixed fraction:$x = 4 + \frac{181}{999}$Wait,checking the repeating decimal $4.185185...$ as a fraction:$x = 4 + \frac{185}{999}$Simplify $\frac{185}{999}$ by dividing by $37$:$185 \div 37 = 5$$999 \div 37 = 27$So,$x = 4 \frac{5}{27}$.

For each question,select the proper option from four options given,to make the statement true: $4 . \overline{185} = \ldots \ldots$

Similar Questions

For each question,select the proper option from four options given,to make the statement true: $\sqrt{5^{2}+12^{2}}$ is a / an $\ldots \ldots$ number.

Represent $\sqrt{10}$ on the number line.

Simplify the following expression: $(\sqrt{11}-\sqrt{3})^{2}$

Simplify the following:
$\sqrt[4]{81}-8 \sqrt[3]{216}+15 \sqrt[5]{32}+\sqrt{225}$

State whether the following statement is true or false. Justify your answer.
$\frac{\sqrt{15}}{\sqrt{3}}$ is written in the form $\frac{p}{q},$ where $q \neq 0,$ so it is a rational number.

Vedclass Test Series

Exam Paper Generator

Online Exam Module