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(D) When a positive integer is divided by $9$,the possible remainders are the set of integers $\{0, 1, 2, 3, 4, 5, 6, 7, 8\}$.There are $9$ possible o

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$1$

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(D) When a positive integer is divided by $9$,the possible remainders are the set of integers $\{0, 1, 2, 3, 4, 5, 6, 7, 8\}$.There are $9$ possible outcomes in total,so $n(S) = 9$.The event $E$ is that the remainder is equal to $1$. This corresponds to the outcome $\{1\}$.Thus,the number of favorable outcomes is $n(E) = 1$.The probability $P(E)$ is given by the ratio of favorable outcomes to total outcomes:$P(E) = \frac{n(E)}{n(S)} = \frac{1}{9}$.

$A$ positive integer is selected at random and is divided by $9$. What is the probability that the remainder is equal to $1$ (in $/9$)?

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