For a wire,frac{R}{l} = frac{1}{2} , Omega/cm | vedclass

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(A) Given: $\frac{R}{l} = \frac{1}{2} \, \Omega/cm$ and $l = 5 \, cm$.
First,calculate the resistance $R$ of the wire:
$R = \frac{1}{2} 	imes l = \

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(A) Given: $\frac{R}{l} = \frac{1}{2} \, \Omega/cm$ and $l = 5 \, cm$.
First,calculate the resistance $R$ of the wire:
$R = \frac{1}{2} 	imes l = \frac{1}{2} 	imes 5 = 2.5 \, \Omega$.
Using Ohm's law,the current $i$ is given by:
$i = \frac{V}{R}$.
Given $V = 1 \, V$,we have:
$i = \frac{1}{2.5} = \frac{10}{25} = 0.4 \, A$.
Therefore,the correct current flowing through the wire is $0.4 \, A$.

For a wire,$\frac{R}{l} = \frac{1}{2} \, \Omega/cm$ and the length of the wire is $l = 5 \, cm$. If a potential difference of $1 \, V$ is applied across it,the current through the wire will be: $(R = \text{Resistance})$ (in $A$)

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