(C) We know that Ohm's law is given by $V = I R$.Substituting $V = E \cdot l$ and $R = \rho \cdot \frac{l}{A}$,where $l$ is the length and $A$ is the

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(C) We know that Ohm's law is given by $V = I R$.Substituting $V = E \cdot l$ and $R = \rho \cdot \frac{l}{A}$,where $l$ is the length and $A$ is the cross-sectional area of the conductor,we get:$E \cdot l = I \cdot \rho \cdot \frac{l}{A}$Dividing both sides by $l$,we get:$E = \left( \frac{I}{A} \right) \rho$Since current density $J = \frac{I}{A}$,we substitute this into the equation:$E = J \rho$ or $E = \rho J$.

Class 12 Physics Current Electricity Ohm's Law

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$E$ is the electric field inside a conductor whose material has conductivity $\sigma$ and resistivity $\rho$. The current density inside the conductor is $J$. The correct form of Ohm's law is

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A
$E=\sigma J$
B
$J=\rho E$
C
$E=\rho J$
D
$E \cdot J=\rho$

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$E$ is the electric field inside a conductor whose material has conductivity $\sigma$ and resistivity $\rho$. The current density inside the conductor is $J$. The correct form of Ohm's law is

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