For a transistor amplifier in common emitter configuration with a load impedance of $1 \ k\Omega$ ($h_{fe} = 50$ and $h_{oe} = 25 \ \mu A/V$),the current gain is:

In the transistor circuit shown,the base current is $35 \mu A$. The value of the resistor $R_b$ is......$ k \Omega$.

For a $CE$ transistor amplifier, the current amplification factor is $59$ and the emitter current is $6.6 \, mA$. Then the base current is

In a $NPN$ transistor,$10^8$ electrons enter the emitter in $10^{-8} \ s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

An unknown transistor needs to be identified as a $npn$ or $pnp$ type. $A$ multimeter,with $+ve$ and $-ve$ terminals,is used to measure resistance between different terminals of the transistor. If terminal $2$ is the base of the transistor,then which of the following is correct for a $pnp$ transistor?

An $npn$ transistor operates as a common emitter amplifier with a power gain of $10^{6}$. The input circuit resistance is $100\, \Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ will be (Round off to the nearest integer).