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(B) For a $pnp$ transistor,the base is $n$-type and the emitter/collector are $p$-type.When the multimeter's $+ve$ terminal is connected to the base (

Vedclass · Accepted Answer

$+ve$ terminal $2,$ $-ve$ terminal $1,$ resistance high

Vedclass · Answer

(B) For a $pnp$ transistor,the base is $n$-type and the emitter/collector are $p$-type.When the multimeter's $+ve$ terminal is connected to the base ($n$-type) and the $-ve$ terminal is connected to the emitter or collector ($p$-type),the junction is reverse-biased.In reverse bias,the resistance is very high.Since terminal $2$ is the base ($n$-type),connecting the $+ve$ terminal of the multimeter to terminal $2$ and the $-ve$ terminal to either terminal $1$ or $3$ ($p$-type) results in high resistance.Therefore,option $B$ is correct.

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