For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is:

In a $p-n-p$ transistor,the current carriers are

$A$ transistor is used in an amplifier circuit in common emitter mode. If the base current changes by $100 \,\mu A$, it brings a change of $10 \,mA$ in collector current. If the load resistance is $2 \,k \Omega$ and input resistance is $1 \,k \Omega$, the value of power gain is $x \times 10^{4}$. The value of $x$ is . . . . . . .

$A$ transistor is connected in common emitter circuit configuration. The collector supply voltage is $10 \, V$ and the voltage drop across a resistor of $1000 \, \Omega$ in the collector circuit is $0.6 \, V$. If the current gain factor $(\beta)$ is $24$,then the base current is $.... \, \mu A$. (Round off to the Nearest Integer)

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $4 \, V$. If the current amplification factor $(\beta)$ of the transistor is $100$ and the base resistance is $1 \, k\Omega$,then the input signal voltage is ....... $mV$.

The part of a transistor which is heavily doped to produce a large number of majority carriers is