$A$ transistor is used in an amplifier circuit in common emitter mode. If the base current changes by $100 \,\mu A$, it brings a change of $10 \,mA$ in collector current. If the load resistance is $2 \,k \Omega$ and input resistance is $1 \,k \Omega$, the value of power gain is $x \times 10^{4}$. The value of $x$ is . . . . . . .

An $n-p-n$ transistor with current gain $\beta=100$ in common emitter configuration is shown in the figure. The output voltage of the amplifier will be $.....V$.

In an $n-p-n$ transistor,

For a given transistor amplifier circuit in $CE$ configuration with $V_{CC} = 1 \text{ V}$,$R_c = 1 \text{ k}\Omega$,$R_b = 100 \text{ k}\Omega$,and $\beta = 100$,the value of the base current $I_b$ is:

In which of the configurations of a transistor, the power gain is highest?

Consider the circuit arrangement shown in figure $(1)$ for studying input and output characteristics of an $n-p-n$ transistor in $CE$ configuration. Select the values of $R_B$ and $R_C$ for a transistor whose $V_{BE} = 0.7 \, V$, so that the transistor is operating at point $Q$ as shown in the characteristics shown in figure $(2)$. Given that the input impedance of the transistor is very small and $V_{CC} = V_{BB} = 16 \, V$, also find the voltage gain and power gain of the circuit making appropriate assumptions.