For a series $LCR$ circuit with $L=2 \ H, C=18 \ \mu F$ and $R=10 \ \Omega$. What is the value of the $Q$ factor of this circuit?

In a series resonant circuit, the $AC$ voltages across resistance $R$, inductor $L$, and capacitor $C$ are $5 \,V$, $10 \,V$, and $10 \,V$ respectively. The $AC$ voltage applied to the circuit will be . . . . . . . (in $V$)

In a series resonant $LCR$ circuit,the voltage across $R$ is $100 \ V$ and $R = 1 \ k\Omega$ with $C = 2 \ \mu F$. The resonant frequency $\omega$ is $200 \ rad/s$. At resonance,the voltage across $L$ is:

An $LCR$ circuit is at resonance for a capacitor $C$,inductance $L$,and resistance $R$. If the value of the resistance is halved while keeping all other parameters the same,the current amplitude at resonance will be:

In a series resonant $R-L-C$ circuit, the voltage across $R$ is $100 \, V$ and the value of $R = 1000 \, \Omega$. The capacitance of the capacitor is $2 \times 10^{-6} \, F$; the angular frequency of the $AC$ source is $200 \, rad \, s^{-1}$. Then the potential difference across the inductance coil is: (in $V$)

$A$ $L-C-R$ series circuit is connected to a source of alternating current. At resonance,the applied voltage and the current flowing through the circuit will have a phase difference of