For a reactions $A + B \to $product, it was found that rate of reaction increases four times if concentration of $ ‘A’$  is doubled, but the rate of reaction remains unaffected. If concentration of $‘B’ $ is doubled. Hence, the rate law for the reaction is

  • A

    ${\rm{rate}} = k[A][B]$

  • B

    ${\rm{rate}} = k{[A]^2}$

  • C

    ${\rm{rate}} = k{[A]^2}{[B]^1}$

  • D

    ${\rm{rate}} = k{[A]^2}{[B]^2}$

Similar Questions

The following results have been obtained during the kinetic studies of the reaction:

$2 A+B \rightarrow C+D$

Experiment  $[ A ] / mol L ^{-1}$ $[ B ] / mol L ^{-1}$ Initial rate of formation of $D / mol \,L ^{-1} \,min ^{-1}$
$I$ $0.1$ $0.1$ $6.0 \times 10^{-3}$
$II$ $0.3$ $0.2$ $7.2 \times 10^{-2}$
$III$ $0.3$ $0.4$ $2.88 \times 10^{-1}$
$IV$ $0.4$ $0.1$ $2.40 \times 10^{-2}$

Determine the rate law and the rate constant for the reaction.

For a reaction $A+ B\to $  Products, the rate law is - Rate $=$ $k\,[A]\, [B]^{\frac {3}{2}}$ . Can the reaction be an elementary reaction ? Explain.

The rate of disappearance of $S{O_2}$ in the reaction $2S{O_2} + {O_2} \to 2S{O_3}$ is $1.28 \times {10^{ - 3}}g/sec$ then the rate of formation of $S{O_3}$ is

Assertion : In rate law, unlike in the expression for equilibrium constants, the exponents for concentrations do not necessarily match the stoichiometric coefficients.

Reason : It is the mechanism and not the balanced chemical equation for the overall change that governs the reaction rate.

  • [AIIMS 2009]

For conversion of compound $A \rightarrow B$, the rate constant of the reaction was found to be $4.6 \times 10^{-5}\,L\, mol ^{-1}\, s ^{-1}$. The order of the reaction is $..........$ 

  • [JEE MAIN 2023]