For a reaction,2 N_2O_{5(g)} longrightarrow | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given reaction is: $2 \ N_2O_{5(g)} \longrightarrow 4 \ NO_{2(g)} + O_{2(g)}$.The rate of reaction is expressed as: $-\frac{1}{2} \frac{d[N_2O

Vedclass · Accepted Answer

$0.12$

Vedclass · Answer

(B) The given reaction is: $2 \ N_2O_{5(g)} \longrightarrow 4 \ NO_{2(g)} + O_{2(g)}$.The rate of reaction is expressed as: $-\frac{1}{2} \frac{d[N_2O_5]}{dt} = \frac{1}{4} \frac{d[NO_2]}{dt}$.Given that the rate of disappearance of $N_2O_5$ is $-\frac{d[N_2O_5]}{dt} = 0.06 \ mol \ dm^{-3} \ s^{-1}$.Substituting this into the rate expression: $\frac{1}{2} 	imes (0.06) = \frac{1}{4} \frac{d[NO_2]}{dt}$.Therefore,the rate of formation of $NO_2$ is: $\frac{d[NO_2]}{dt} = 2 	imes 0.06 = 0.12 \ mol \ dm^{-3} \ s^{-1}$.

For a reaction,$2 \ N_2O_{5(g)} \longrightarrow 4 \ NO_{2(g)} + O_{2(g)}$. The $N_2O_5$ disappears at a rate of $0.06 \ mol \ dm^{-3} \ s^{-1}$. What is the rate of $NO_{2(g)}$ formation (in $mol \ dm^{-3} \ s^{-1}$)?

Similar Questions

For the reaction,$N_2 + 3H_2 \rightarrow 2NH_3,$ if $\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \ mol \ L^{-1} \ s^{-1},$ the value of $-\frac{d[H_2]}{dt}$ would be .................. $mol \ L^{-1} \ s^{-1}$.

Consider the reaction $3 I^{-} + S_2 O_8^{2-} \longrightarrow I_3^{-} + 2 SO_4^{2-}$. At a particular time $t$,$\frac{d[SO_4^{2-}]}{dt}$ is $2.2 \times 10^{-2} \ mol \ dm^{-3} \ s^{-1}$. What is the value of $\frac{d[S_2 O_8^{2-}]}{dt}$?

For a general chemical reaction $2A + 3B \rightarrow \text{Products}$,if the rate of disappearance of $A$ is $r_1$ and that of $B$ is $r_2$,then the relationship between $r_1$ and $r_2$ is:

Thermal decomposition of $N_2O_5$ occurs as per the equation below:
$2N_2O_5 \longrightarrow 4NO_2 + O_2$
The correct statement is:

For the reaction $I_2 + 2S_2O_3^{2-} \rightarrow 2I^{-} + S_4O_6^{2-}$,which of the following expressions correctly represents the rate of reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module