For a reaction,$I^{-} + OCl^{-} \to IO^{-} + Cl^{-}$ in an aqueous medium,the rate of reaction is given by $\frac{d[IO^{-}]}{dt} = k[I^{-}][OCl^{-}]$. The overall order of reaction is

  • A
    $1$
  • B
    $0$
  • C
    $1$
  • D
    $2$

Explore More

Similar Questions

What is the molecularity of the following reactions?
$1.$ $NH_4NO_2(s) \rightarrow N_2(g) + 2H_2O(l)$
$2.$ $2HI(g) \rightarrow H_2(g) + I_2(g)$
$3.$ $2NO(g) + O_2(g) \rightarrow 2NO_2(g)$

Difficult
View Solution

For the reaction $A + 2B \rightarrow \text{Product } (P)$,the rate law is given by $\frac{d[P]}{dt} = K[A]^2[B]$. If $[A]$ is taken in large excess,what will be the order of the reaction?

Which of the following is $NOT$ true about the order of a reaction?

For the reaction $RCl + NaOH_{(aq)} \rightarrow ROH + NaCl$,the rate is given by $Rate = K_1[RCl]$. What will happen to the reaction rate?

Consider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
Experiment No. $[A] \ (mol \ dm^{-3})$ $[B] \ (mol \ dm^{-3})$ $[C] \ (mol \ dm^{-3})$ Rate of reaction $(mol \ dm^{-3} \ s^{-1})$
$1$ $0.2$ $0.1$ $0.1$ $6.0 \times 10^{-5}$
$2$ $0.2$ $0.2$ $0.1$ $6.0 \times 10^{-5}$
$3$ $0.2$ $0.1$ $0.2$ $1.2 \times 10^{-4}$
$4$ $0.3$ $0.1$ $0.1$ $9.0 \times 10^{-5}$

The rate of the reaction for $[A]=0.15 \ mol \ dm^{-3}, [B]=0.25 \ mol \ dm^{-3}$ and $[C]=0.15 \ mol \ dm^{-3}$ is found to be $Y \times 10^{-5} \ mol \ dm^{-3} \ s^{-1}$. The value of $Y$ is . . . . . .

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo