For a given frequency distribution,bar{x} = 1 | vedclass

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(A) The formula for the mean using the assumed mean method is given by: $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{n}$.Given values are $\bar{x} = 19.7$

Vedclass · Accepted Answer

$-15$

Vedclass · Answer

(A) The formula for the mean using the assumed mean method is given by: $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{n}$.Given values are $\bar{x} = 19.7$,$A = 20$,and $n = 50$.Substituting these values into the formula:$19.7 = 20 + \frac{\Sigma f_{i} d_{i}}{50}$.Subtracting $20$ from both sides:$19.7 - 20 = \frac{\Sigma f_{i} d_{i}}{50}$.$-0.3 = \frac{\Sigma f_{i} d_{i}}{50}$.Multiplying both sides by $50$:$\Sigma f_{i} d_{i} = -0.3 	imes 50$.$\Sigma f_{i} d_{i} = -15$.

Class	$0-100$	$100-200$	$200-300$	$300-400$	$400-500$	$500-600$
Frequency	$12$	$18$	$27$	$20$	$17$	$6$

For a given frequency distribution,$\bar{x} = 19.7$,$A = 20$,and $n = 50$. Then,$\Sigma f_{i} d_{i} = \ldots$

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