Find the mode of the following frequency dist | vedclass

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(B) The modal class is the class with the highest frequency. Here,the highest frequency is $37$,which corresponds to the class interval $200-300$.Thus

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$240$

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(B) The modal class is the class with the highest frequency. Here,the highest frequency is $37$,which corresponds to the class interval $200-300$.Thus,the modal class is $200-300$.We use the formula for mode: $Z = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$Where:$l$ (lower limit of modal class) $= 200$$h$ (class size) $= 100$$f_1$ (frequency of modal class) $= 37$$f_0$ (frequency of the class preceding the modal class) $= 21$$f_2$ (frequency of the class succeeding the modal class) $= 13$Substituting these values into the formula:$Z = 200 + \left( \frac{37 - 21}{2(37) - 21 - 13} ight) 	imes 100$$Z = 200 + \left( \frac{16}{74 - 34} ight) 	imes 100$$Z = 200 + \left( \frac{16}{40} ight) 	imes 100$$Z = 200 + 0.4 	imes 100$$Z = 200 + 40 = 240$Therefore,the mode of the given frequency distribution is $240$.

Class (seconds)	$13.8-14.0$	$14.0-14.2$	$14.2-14.4$	$14.4-14.6$	$14.6-14.8$	$14.8-15.0$
Frequency	$2$	$4$	$5$	$71$	$48$	$20$

Find the mode of the following frequency distribution:

Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$

Frequency $7$ $21$ $37$ $13$ $12$ $10$

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Class (seconds) $13.8-14.0$ $14.0-14.2$ $14.2-14.4$ $14.4-14.6$ $14.6-14.8$ $14.8-15.0$

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Find the mode of the following frequency distribution: Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ Frequency $7$ $21$ $37$ $13$ $12$ $10$