For a given frequency distribution,bar{x}=20, | vedclass

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(A) The formula for the mean using the step-deviation method is given by: $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{n} ight) 	imes c$Given va

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$25$

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(A) The formula for the mean using the step-deviation method is given by: $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{n} ight) 	imes c$Given values are: $\bar{x} = 20$,$\Sigma f_{i} u_{i} = -50$,$n = 100$,and $c = 10$.Substituting these values into the formula:$20 = A + \left( \frac{-50}{100} ight) 	imes 10$Simplify the expression:$20 = A + (-0.5) 	imes 10$$20 = A - 5$Solving for $A$:$A = 20 + 5$$A = 25$Thus,the assumed mean $A$ is $25$.

Class	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$
Frequency	$2$	$10$	$40$	$25$	$13$	$10$

For a given frequency distribution,$\bar{x}=20, \Sigma f_{i} u_{i}=-50, n=100$ and $c=10$. Then,assumed mean $A = \ldots \ldots \ldots \ldots$

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