For 0 leq P, Q leq frac{pi}{2}, if sin P + co | vedclass

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(A) Given,$0 \leq P, Q \leq \frac{\pi}{2}$ and $\sin P + \cos Q = 2.$Since the maximum value of $\sin P$ is $1$ and the maximum value of $\cos Q$ is $

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$1$

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(A) Given,$0 \leq P, Q \leq \frac{\pi}{2}$ and $\sin P + \cos Q = 2.$Since the maximum value of $\sin P$ is $1$ and the maximum value of $\cos Q$ is $1,$ the equation $\sin P + \cos Q = 2$ holds only when $\sin P = 1$ and $\cos Q = 1.$For $0 \leq P \leq \frac{\pi}{2},$ $\sin P = 1$ implies $P = \frac{\pi}{2}.$For $0 \leq Q \leq \frac{\pi}{2},$ $\cos Q = 1$ implies $Q = 0.$Therefore,$	an \left(\frac{P + Q}{2}ight) = 	an \left(\frac{\frac{\pi}{2} + 0}{2}ight) = 	an \left(\frac{\pi}{4}ight) = 1.$

For $0 \leq P, Q \leq \frac{\pi}{2},$ if $\sin P + \cos Q = 2,$ then the value of $\tan \left(\frac{P + Q}{2}\right)$ is equal to

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