$x>0$ માટે,જો $y=\frac{10^{\log _{10} x}}{x^{2}}$ અને $x=y^{a}$ હોય,તો $a=$

$\log _{5}\left(1+\frac{1}{5}\right)+\log _{5}\left(1+\frac{1}{6}\right)+\log _{5}\left(1+\frac{1}{7}\right)+\cdots+\log _{5} \left(1+\frac{1}{624}\right)$

જો $\log_{10} 2 = 0.3010$ હોય,તો $\log_{10}(1/2) =$

જો $\log _{a} b=\log _{b} c=\log _{c} a$ હોય,તો:

જો $\log _{e} 2 \cdot \log _{b} 625 = \log _{10} 16 \cdot \log _{e} 10$ હોય,તો $b =$

$7 \log \frac{16}{15} + 5 \log \frac{25}{24} + 3 \log \frac{81}{80} =$