In the given arrangement,the normal force app | vedclass

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(B) To find the normal force,we analyze the forces acting on the block in the vertical direction.The forces acting vertically are:$1$. The gravitation

Vedclass · Accepted Answer

$mg - F \cos 	heta$

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(B) To find the normal force,we analyze the forces acting on the block in the vertical direction.The forces acting vertically are:$1$. The gravitational force $mg$ acting downwards.$2$. The normal force $N$ exerted by the ground on the block,acting upwards.$3$. The vertical component of the applied force $F$. Since the angle $	heta$ is given with the vertical,the vertical component is $F \cos 	heta$,acting upwards.For the block to be in vertical equilibrium,the sum of upward forces must equal the sum of downward forces:$N + F \cos 	heta = mg$Rearranging for the normal force $N$:$N = mg - F \cos 	heta$Thus,the normal force applied by the block on the ground is equal to the normal force exerted by the ground on the block,which is $mg - F \cos 	heta$.Hence,option $(B)$ is the correct answer.

In the given arrangement,the normal force applied by the block on the ground is

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