In the given arrangement,the normal force applied by the block on the ground is

  • A
    $mg$
  • B
    $mg - F \cos \theta$
  • C
    $mg + F \cos \theta$
  • D
    $F \cos \theta$

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Similar Questions

$A$ block of mass $90 \,kg$ is suspended by three strings $A, B$ and $C$ as shown in the figure. Find the tensions in the strings $A, B$ and $C$ respectively. $\left(g=10 \,ms^{-2}, \sin 37^{\circ}=0.6, \cos 37^{\circ}=0.8\right)$

Statement-$I$: If three forces $\vec{F}_{1}, \vec{F}_{2}$ and $\vec{F}_{3}$ are represented by three sides of a triangle and $\vec{F}_{1} + \vec{F}_{2} = -\vec{F}_{3}$,then these three forces are concurrent forces and satisfy the condition for equilibrium.
Statement-$II$: $A$ triangle made up of three forces $\vec{F}_{1}, \vec{F}_{2}$ and $\vec{F}_{3}$ as its sides taken in the same order,satisfy the condition for translatory equilibrium.
In the light of the above statements,choose the most appropriate answer from the options given below:

There are four forces acting at a point $P$ produced by strings as shown in the figure. The system is at rest. Find the forces $F_1$ and $F_2$.

The sum of three forces $\vec F_1 = 100\,N$,$\vec F_2 = 80\,N$,and $\vec F_3 = 60\,N$ acting on a particle is zero. The angle between $\vec F_1$ and $\vec F_2$ is nearly .......... $^o$

The adjacent figure shows a part of a horizontally stretched net. Section $AB$ is stretched with a force of $10 \,N$. The tensions in the sections $BC$ and $BF$ are

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