Focus of the parabola ${(y - 2)^2} = 20(x + 3)$ is

Let $ABCD$ be a trapezium whose vertices lie on the parabola $y^2=4x$. Let the sides $AD$ and $BC$ of the trapezium be parallel to the $y$-axis. If the diagonal $AC$ is of length $\frac{25}{4}$ and it passes through the point $(1,0)$,then the area of $ABCD$ is:

The axis of a parabola is the line $y=x$ and its vertex and focus are in the first quadrant at distances $\sqrt{2}$ and $2\sqrt{2}$ units from the origin,respectively. If the point $(1, k)$ lies on the parabola,then a possible value of $k$ is :-

The equations of the normals at the ends of the latus rectum of the parabola $y^{2}=4ax$ are given by

The line among the following which touches the parabola $y^2=4ax$ is

The area of the triangle formed by the lines joining the vertex of the parabola $x^2=12y$ to the ends of its latus rectum is equal to $...$ sq. units.