Find which of the variables $x, y, z$ and $u$ represent rational numbers and which irrational numbers:
$(i)$ $x^{2}=5$
$(ii)$ $y^{2}=9$
$(iii)$ $z^{2}=0.04$
$(iv)$ $u^{2}=\frac{17}{4}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) $(i)$ $x^{2}=5 \Rightarrow x=\sqrt{5},$ which is an irrational number because $\sqrt{5}$ cannot be expressed in the form $\frac{p}{q}$ where $p, q$ are integers and $q \neq 0$.
$(ii)$ $y^{2}=9 \Rightarrow y=\sqrt{9}=3,$ which is a rational number because it can be expressed as $\frac{3}{1}$.
$(iii)$ $z^{2}=0.04 \Rightarrow z=\sqrt{0.04}=0.2,$ which is a rational number because it is a terminating decimal and can be written as $\frac{2}{10} = \frac{1}{5}$.
$(iv)$ $u^{2}=\frac{17}{4} \Rightarrow u=\sqrt{\frac{17}{4}}=\frac{\sqrt{17}}{2}.$ Since $\sqrt{17}$ is not an integer,$u$ is an irrational number.

Explore More

Similar Questions

Rationalise the denominator of the following: $\frac{\sqrt{40}}{\sqrt{3}}$

Let $x$ and $y$ be rational and irrational numbers,respectively. Is $x+y$ necessarily an irrational number? Give an example in support of your answer.

If $\sqrt{5} = 2.236$,then evaluate $\frac{4 - \sqrt{5}}{\sqrt{5}}$ correct to four decimal places.

Simplify: $(3 \sqrt{5}-5 \sqrt{2})(4 \sqrt{5}+3 \sqrt{2})$

Difficult
View Solution

Write the following in decimal form and state what kind of decimal expansion each has:
$\frac{2}{11}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo