Find the velocity of the hanging block if the velocities of the free ends of the rope are as indicated in the figure.
$\frac{3}{2}\,m / s \uparrow$
$\frac{3}{2}\,m / s \downarrow$
$\frac{1}{2}\,m / s \uparrow$
$\frac{1}{2}\,m / s \downarrow$
For the given diagram when block $B$ is pulled with velocity $V$ then velocity of block $A$ will be :-
In the figure shown the block $B$ moves down with a velocity $10 m/s$. The velocity of $A$ in the position shown is ......... $m/s$
The end $B$ of the rod $AB$ which makes angle $\theta$ with the floor is being pulled with, a constant velocity $v_0$ as shown. The length of the rod is $l.$ At the instant when $\theta = 37^o $ then
A block of mass $M$ is tied to one end of massless rope. The other end of rope is in the hands of a man of mass $2M$ as show in figure. Initially the block and the man are resting on a rough plank of mass $2M$ as shown in figure. The whole system is resting on a smooth horizontal surface. The man pulls the rope. Pulley is massless and frictionless. What is the magnitude of displacement of the plank when the block meets the pulley ......... $m $ (Man does not leave his position on the plank during the pull).
In the figure shown the velocity of lift is $2\,m / s$ while string is winding on the motor shaft with velocity $2\,m / s$ and block $A$ is moving downwards with a velocity of $2\,m / s$, then find out the velocity of block $B -$