Find the value of a, b, c, and d from the equ | vedclass

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(B) Given the matrix equation: $\begin{bmatrix} a-b & 2a+c \ 2a-b & 3c+d \end{bmatrix} = \begin{bmatrix} -1 & 5 \ 0 & 13 \end{bmatrix}$Since the two

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$a=1, b=2, c=3, d=4$

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(B) Given the matrix equation: $\begin{bmatrix} a-b & 2a+c \ 2a-b & 3c+d \end{bmatrix} = \begin{bmatrix} -1 & 5 \ 0 & 13 \end{bmatrix}$Since the two matrices are equal,their corresponding elements must be equal.Comparing the corresponding elements,we get:$a-b = -1$  $(1)$$2a-b = 0$  $(2)$$2a+c = 5$  $(3)$$3c+d = 13$  $(4)$From equation $(2)$,we have $b = 2a$.Substituting $b = 2a$ into equation $(1)$:$a - 2a = -1$$-a = -1 \Rightarrow a = 1$Now,find $b$ using $b = 2a$:$b = 2(1) = 2$Substitute $a = 1$ into equation $(3)$:$2(1) + c = 5$$2 + c = 5 \Rightarrow c = 3$Substitute $c = 3$ into equation $(4)$:$3(3) + d = 13$$9 + d = 13 \Rightarrow d = 4$Therefore,the values are $a=1, b=2, c=3,$ and $d=4$.

Find the value of $a, b, c,$ and $d$ from the equation: $\begin{bmatrix} a-b & 2a+c \\ 2a-b & 3c+d \end{bmatrix} = \begin{bmatrix} -1 & 5 \\ 0 & 13 \end{bmatrix}$

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