Find the sum of the first 20 terms of the A.P | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given $A.P.$ is $50, 46, 42, \ldots$Here,the first term $a = 50$ and the common difference $d = 46 - 50 = -4$.The number of terms $n = 20$.The

Vedclass · Accepted Answer

$240$

Vedclass · Answer

(C) The given $A.P.$ is $50, 46, 42, \ldots$Here,the first term $a = 50$ and the common difference $d = 46 - 50 = -4$.The number of terms $n = 20$.The sum of the first $n$ terms of an $A.P.$ is given by the formula $S_n = \frac{n}{2} [2a + (n - 1)d]$.Substituting the values: $S_{20} = \frac{20}{2} [2(50) + (20 - 1)(-4)]$.$S_{20} = 10 [100 + 19(-4)]$.$S_{20} = 10 [100 - 76]$.$S_{20} = 10 [24] = 240$.Therefore,the sum of the first $20$ terms is $240$.

Find the sum of the first $20$ terms of the $A.P.$ $50, 46, 42, \ldots$

Similar Questions

The first term of a finite $A.P.$ is $5$ and its last term is $45$. If the sum of all the terms is $500$,there are $\ldots$ terms in the $A.P.$

The $4^{\text{th}}$ term from the end of the $AP: -11, -8, -5, \dots, 49$ is

Write the first three terms of the $APs$ when $a$ and $d$ are as given below:
$a=\sqrt{2}, d=\frac{1}{\sqrt{2}}$

Split $207$ into three parts such that these are in $AP$ and the product of the two smaller parts is $4623$.

The sum of the first twenty even natural numbers is $\ldots \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module