Find the roots of the equation 2x^{2}-5x+3=0 | vedclass

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Question

(A) To find the roots of the quadratic equation $2x^{2}-5x+3=0$ by factorisation,we split the middle term $-5x$ into $-2x$ and $-3x$,because $(-2x)

Vedclass · Accepted Answer

$1, \frac{3}{2}$

Vedclass · Answer

(A) To find the roots of the quadratic equation $2x^{2}-5x+3=0$ by factorisation,we split the middle term $-5x$ into $-2x$ and $-3x$,because $(-2x) 	imes (-3x) = 6x^{2}$,which is the product of the coefficient of $x^{2}$ $(2)$ and the constant term $(3)$.Now,rewrite the equation as:$2x^{2}-2x-3x+3=0$Factor by grouping:$2x(x-1)-3(x-1)=0$$(2x-3)(x-1)=0$Setting each factor to zero:$2x-3=0 \implies 2x=3 \implies x=\frac{3}{2}$$x-1=0 \implies x=1$Thus,the roots of the equation are $x=1$ and $x=\frac{3}{2}$.

Find the roots of the equation $2x^{2}-5x+3=0$ by factorisation.

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