Find the discriminant of the quadratic equation $2x^{2}-4x+3=0$,and hence find the nature of its roots.
(D) The given quadratic equation is in the form $ax^{2}+bx+c=0$,where $a=2$,$b=-4$,and $c=3$.
The discriminant $D$ is given by the formula $D = b^{2}-4ac$.
Substituting the values,we get:
$D = (-4)^{2} - (4 \times 2 \times 3)$
$D = 16 - 24$
$D = -8$
Since the discriminant $D < 0$,the quadratic equation has no real roots.
The discriminant $D$ is given by the formula $D = b^{2}-4ac$.
Substituting the values,we get:
$D = (-4)^{2} - (4 \times 2 \times 3)$
$D = 16 - 24$
$D = -8$
Since the discriminant $D < 0$,the quadratic equation has no real roots.
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