Find the power of the circuit in W. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a steady state,the branches containing capacitors act as open circuits and can be neglected. Thus,the current flows only through the resistors

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) In a steady state,the branches containing capacitors act as open circuits and can be neglected. Thus,the current flows only through the resistors in the bottom and middle branches. The equivalent resistance of the circuit is $R_{eq} = 2\,\Omega + 2\,\Omega = 4\,\Omega$. The power consumed by the circuit is given by $P = \frac{V^2}{R_{eq}}$. Substituting the values,$P = \frac{(2)^2}{4} = \frac{4}{4} = 1\,W$.

Find the power of the circuit in $W$.

Similar Questions

The current in the following circuit is ........... $A$.

Find the electric potential at points $C$ and $D$ in the given circuit.

$A$ current of $2\,A$ flows through a $2\,\Omega$ resistor when connected across a battery. The same battery supplies a current of $0.5\,A$ when connected across a $9\,\Omega$ resistor. The internal resistance of the battery is:

In the given circuit,the current flowing through the circuit is: (in $A$)

$A$ cell of constant $e.m.f.$ is connected first to an external resistance $R_1$ and then to an external resistance $R_2$. If the power consumed in both cases is the same,what is the internal resistance of the cell?

Vedclass Test Series

Exam Paper Generator

Online Exam Module