Which of the four resistances P, Q, R and S g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The circuit consists of two parallel branches. The upper branch has resistances $P = 2 \, \Omega$ and $Q = 4 \, \Omega$ in series,so its total res

Vedclass · Accepted Answer

$S$

Vedclass · Answer

(B) The circuit consists of two parallel branches. The upper branch has resistances $P = 2 \, \Omega$ and $Q = 4 \, \Omega$ in series,so its total resistance is $R_1 = P + Q = 2 \, \Omega + 4 \, \Omega = 6 \, \Omega$.The lower branch has resistances $R = 1 \, \Omega$ and $S = 2 \, \Omega$ in series,so its total resistance is $R_2 = R + S = 1 \, \Omega + 2 \, \Omega = 3 \, \Omega$.Since the branches are in parallel,the potential difference across them is the same. Let $I_1$ be the current in the upper branch and $I_2$ be the current in the lower branch.$I_1 R_1 = I_2 R_2 \implies I_1 (6 \, \Omega) = I_2 (3 \, \Omega) \implies I_2 = 2 I_1$.The heat generated in a resistor is given by $H = I^2 R t$.For $P$: $H_P = I_1^2 P t = I_1^2 (2) t = 2 I_1^2 t$.For $Q$: $H_Q = I_1^2 Q t = I_1^2 (4) t = 4 I_1^2 t$.For $R$: $H_R = I_2^2 R t = (2 I_1)^2 (1) t = 4 I_1^2 t$.For $S$: $H_S = I_2^2 S t = (2 I_1)^2 (2) t = 8 I_1^2 t$.Comparing the heat values,$H_S = 8 I_1^2 t$ is the greatest. Therefore,the resistance $S$ generates the greatest amount of heat.

Which of the four resistances $P, Q, R$ and $S$ generate the greatest amount of heat when a current flows from $A$ to $B$?

Similar Questions

In the given circuit,$E_1 = E_2 = E_3 = 2 \, V$ and $R_1 = R_2 = 4 \, \Omega$. What is the current flowing between points $A$ and $B$ (in $, A$)?

$A$ battery of $e.m.f.$ $3\, V$ and internal resistance $1.0\, \Omega$ is connected in series with a copper voltameter. The current flowing in the circuit is $1.5\, A$. The resistance of the voltameter will be ........... $\Omega$.

$A$ $50\, W$ bulb is in series with a room heater and the combination is connected across the mains. To get maximum heater output,the $50\, W$ bulb should be replaced by a bulb of: (in $, W$)

In the given circuit,find the charge on the capacitors.

$A$ current of $2\,A$ flows through a $2\,\Omega$ resistor when connected across a battery. The same battery supplies a current of $0.5\,A$ when connected across a $9\,\Omega$ resistor. The internal resistance of the battery is

Vedclass Test Series

Exam Paper Generator

Online Exam Module