Find the mode of the following frequency dist | vedclass

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(B) The formula for the mode of a grouped frequency distribution is given by:$Mode = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$$1

Vedclass · Accepted Answer

$46$

Vedclass · Answer

(B) The formula for the mode of a grouped frequency distribution is given by:$Mode = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$$1$. Identify the modal class: The class with the highest frequency is $40-50$,so the modal class is $40-50$.$2$. Identify the parameters:- Lower limit of the modal class $(l)$ = $40$- Frequency of the modal class $(f_1)$ = $42$- Frequency of the class preceding the modal class $(f_0)$ = $24$- Frequency of the class succeeding the modal class $(f_2)$ = $30$- Class size $(h)$ = $10$$3$. Substitute the values into the formula:$Mode = 40 + \left( \frac{42 - 24}{2(42) - 24 - 30} ight) 	imes 10$$Mode = 40 + \left( \frac{18}{84 - 54} ight) 	imes 10$$Mode = 40 + \left( \frac{18}{30} ight) 	imes 10$$Mode = 40 + \left( \frac{18}{3} ight) = 40 + 6 = 46$Thus,the mode is $46$.

Weight (in $kg$)	$100-110$	$110-120$	$120-130$	$130-140$	$140-150$
Number of wrestlers	$4$	$14$	$21$	$8$	$3$

Class	$0-5$	$5-10$	$10-15$	$15-20$	$20-25$
Frequency	$10$	$15$	$12$	$20$	$9$

Find the mode of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $6$ $8$ $17$ $24$ $42$ $30$ $15$ $8$

Similar Questions

The weights (in $kg$) of $50$ wrestlers are recorded in the following table:

Weight (in $kg$) $100-110$ $110-120$ $120-130$ $130-140$ $140-150$

Number of wrestlers $4$ $14$ $21$ $8$ $3$

Find the mean weight of the wrestlers (in $kg$).

Find the mean,median,and mode of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$

Frequency $5$ $27$ $58$ $20$ $10$

For some given data, if $M = 15.4$ and $\bar{x} = 14.5$, then $Z = \dots$

For the following distribution:

Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$

Frequency $10$ $15$ $12$ $20$ $9$

the sum of the lower limits of the median class and the modal class is:

For a given frequency distribution,$A=325, c=50, \Sigma f_{i} u_{i}=28$ and $\Sigma f_{i}=200$. Then,mean $\bar{x}=\ldots \ldots \ldots . .$

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Find the mode of the following frequency distribution: Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $6$ $8$ $17$ $24$ $42$ $30$ $15$ $8$