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(B) To find the median,we first calculate the cumulative frequency $(cf)$:ClassFrequency $(f)$Cumulative Frequency $(cf)$$0-20$$5$$5$$20-40$$15$$20$$4

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$50$

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(B) To find the median,we first calculate the cumulative frequency $(cf)$:ClassFrequency $(f)$Cumulative Frequency $(cf)$$0-20$$5$$5$$20-40$$15$$20$$40-60$$20$$40$$60-80$$18$$58$$80-100$$2$$60$Total frequency $N = 60$. So,$N/2 = 60/2 = 30$.The cumulative frequency just greater than $30$ is $40$,which corresponds to the median class $40-60$.Here,lower limit $l = 40$,class size $h = 20$,frequency of median class $f = 20$,and cumulative frequency of the class preceding the median class $cf = 20$.Using the median formula: $	ext{Median} = l + \left( \frac{\frac{N}{2} - cf}{f} ight) 	imes h$$	ext{Median} = 40 + \left( \frac{30 - 20}{20} ight) 	imes 20$$	ext{Median} = 40 + \left( \frac{10}{20} ight) 	imes 20 = 40 + 10 = 50$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$6$	$8$	$16$	$20$	$18$	$16$	$14$

Find the median of the following frequency distribution:
Class $0-20$ $20-40$ $40-60$ $60-80$ $80-100$
Frequency $5$ $15$ $20$ $18$ $2$

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Class	$0-20$	$20-40$	$40-60$	$60-80$	$80-100$
Frequency	$5$	$15$	$20$	$18$	$2$

Find the median of the following frequency distribution:Class$0-20$$20-40$$40-60$$60-80$$80-100$Frequency$5$$15$$20$$18$$2$