Find the median of the following frequency di | vedclass

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(B) 						Class			Frequency $(f)$			Cumulative frequency $(cf)$							$5-10$			$5$			$5$							$10-15$			$6$			$11$							$15-20$			$15$			$26$

Vedclass · Accepted Answer

$19.5$

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(B) 						Class			Frequency $(f)$			Cumulative frequency $(cf)$							$5-10$			$5$			$5$							$10-15$			$6$			$11$							$15-20$			$15$			$26$							$20-25$			$10$			$36$							$25-30$			$5$			$41$							$30-35$			$4$			$45$							$35-40$			$2$			$47$							$40-45$			$2$			$49$			Here,the total frequency $n = 49$.$	herefore \frac{n}{2} = \frac{49}{2} = 24.5$.The cumulative frequency just greater than $24.5$ is $26$,which corresponds to the class interval $15-20$.Therefore,the median class is $15-20$.Here,$l = 15$ (lower limit of median class),$cf = 11$ (cumulative frequency of the class preceding the median class),$f = 15$ (frequency of the median class),and $h = 5$ (class size).Using the median formula: $M = l + \left( \frac{\frac{n}{2} - cf}{f} ight) 	imes h$$M = 15 + \left( \frac{24.5 - 11}{15} ight) 	imes 5$$M = 15 + \left( \frac{13.5}{15} ight) 	imes 5$$M = 15 + \frac{13.5}{3} = 15 + 4.5 = 19.5$.Thus,the median of the given frequency distribution is $19.5$.

Marks obtained	Number of students
More than or equal to $0$	$63$
More than or equal to $10$	$58$
More than or equal to $20$	$55$
More than or equal to $30$	$51$
More than or equal to $40$	$48$
More than or equal to $50$	$42$

Find the median of the following frequency distribution:

Class $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ $30-35$ $35-40$ $40-45$

Frequency $5$ $6$ $15$ $10$ $5$ $4$ $2$ $2$

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Class	$5-10$	$10-15$	$15-20$	$20-25$	$25-30$	$30-35$	$35-40$	$40-45$
Frequency	$5$	$6$	$15$	$10$	$5$	$4$	$2$	$2$

Find the median of the following frequency distribution: Class $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ $30-35$ $35-40$ $40-45$ Frequency $5$ $6$ $15$ $10$ $5$ $4$ $2$ $2$